17 October, 2013

Slc-5 Series

Calculate the volume of carbon dioxide gas produced, at SLC, when 5. 00 g of calcium carbonate is added to a solution containing 5. 00 g of nitric acid. I was happy to learn… Let us try it. Write the reaction first CaCO3 + 2 HNO3 ————–> Ca(NO3)2 + CO2 + H2O mol wt of CaCO3 = 40 + 12 + 48 = 100 5 g = 5/100 = 0. 05 moles Now 1 mole of CaCO3 gives 1 mole of CO2 so 0. 05 moles will give 0. 05 moles of CO2 Now at STP 1 mole will occupy 22. 4 L, so 0. 05 moles will occupy 22. 4*0. 05 = 1. 12 L You may want to use the value for volume of 1 mole of gas at SLC to get the correct answer, I do not remember it off hand but it is closer to 24 L or something like that. So your actual answer at SLC will be somewhat higher than 1. 12 L

This is for Windows 7 32 bit PC and Allen Bradley 1747-UIC to a 1747-L532 SLC 5/03 PLC. . . Also good for fixed SLC's, 5/02 and 5/01 For all your automation an. . .


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